(b-3)(b^2+3b+9)=0

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Solution for (b-3)(b^2+3b+9)=0 equation:


Simplifying
(b + -3)(b2 + 3b + 9) = 0

Reorder the terms:
(-3 + b)(b2 + 3b + 9) = 0

Reorder the terms:
(-3 + b)(9 + 3b + b2) = 0

Multiply (-3 + b) * (9 + 3b + b2)
(-3(9 + 3b + b2) + b(9 + 3b + b2)) = 0
((9 * -3 + 3b * -3 + b2 * -3) + b(9 + 3b + b2)) = 0
((-27 + -9b + -3b2) + b(9 + 3b + b2)) = 0
(-27 + -9b + -3b2 + (9 * b + 3b * b + b2 * b)) = 0
(-27 + -9b + -3b2 + (9b + 3b2 + b3)) = 0

Reorder the terms:
(-27 + -9b + 9b + -3b2 + 3b2 + b3) = 0

Combine like terms: -9b + 9b = 0
(-27 + 0 + -3b2 + 3b2 + b3) = 0
(-27 + -3b2 + 3b2 + b3) = 0

Combine like terms: -3b2 + 3b2 = 0
(-27 + 0 + b3) = 0
(-27 + b3) = 0

Solving
-27 + b3 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '27' to each side of the equation.
-27 + 27 + b3 = 0 + 27

Combine like terms: -27 + 27 = 0
0 + b3 = 0 + 27
b3 = 0 + 27

Combine like terms: 0 + 27 = 27
b3 = 27

Simplifying
b3 = 27

Reorder the terms:
-27 + b3 = 27 + -27

Combine like terms: 27 + -27 = 0
-27 + b3 = 0

The solution to this equation could not be determined.

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